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8x+4=3x^2-0.75
We move all terms to the left:
8x+4-(3x^2-0.75)=0
We get rid of parentheses
-3x^2+8x+0.75+4=0
We add all the numbers together, and all the variables
-3x^2+8x+4.75=0
a = -3; b = 8; c = +4.75;
Δ = b2-4ac
Δ = 82-4·(-3)·4.75
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-11}{2*-3}=\frac{-19}{-6} =3+1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+11}{2*-3}=\frac{3}{-6} =-1/2 $
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